CH_3-CHCl-CH_2-CH_3 xrightarrow[Delta]{KOH} t | vedclass

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Question

(C) The reaction is the dehydrohalogenation of $2$-chlorobutane using an alcoholic base $(KOH)$.The base removes a $\beta$-hydrogen and a chloride ion

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$3$

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(C) The reaction is the dehydrohalogenation of $2$-chlorobutane using an alcoholic base $(KOH)$.The base removes a $\beta$-hydrogen and a chloride ion to form alkenes.The possible products are:$1.$ But-$1$-ene $(CH_2=CH-CH_2-CH_3)$$2.$ $cis$-But-$2$-ene $(CH_3-CH=CH-CH_3)$$3.$ $trans$-But-$2$-ene $(CH_3-CH=CH-CH_3)$Since But-$2$-ene exhibits geometrical isomerism,it exists as two distinct stereoisomers. Therefore,the total number of elimination products is $3$.

$CH_3-CHCl-CH_2-CH_3 \xrightarrow[\Delta]{KOH} \text{product}$
The possible number of elimination products (alkene) of the given reaction is?

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$CH_3-CHCl-CH_2-CH_3 \xrightarrow[\Delta]{KOH} \text{product}$The possible number of elimination products (alkene) of the given reaction is?